17x^2+32x+15=0

Solution for 17x^2+32x+15=0 equation:

17x^2+32x+15=0

a = 17; b = 32; c = +15;
Δ = b2-4ac
Δ = 322-4·17·15
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-2}{2*17}=\frac{-34}{34}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+2}{2*17}=\frac{-30}{34}
=-15/17
$